Problem: In one month's time, a coal fired electrical generating plant burns 30,000 tons of coal and generates 20,000 mwh (megawatt hours) of electricity. A pound of coal produces 5000 BTUs and one kwh (kilowatt hour) is equivalent to 3400 BTUs.
a) Calculate the efficiency of the power plant.
b) The Environmental Protection Agency (EPA) standard for power plants, such as this one, is that no more than 2.2 pounds of sulfur be emitted per million BTUs released by burning coal. Assuming coal contains 1% sulfur by weight, determine whether the power plant meets the EPS standard.Environmental math problems! please help me?a)
efficiency = power output / power input
1 (short) ton = 2000 pounds
1 (long) ton = 2240 pounds
1 (metric) ton = 2204.62248 pounds
Which measurement do you use? I'll assume short tons.
30000 tons = 30000*2000 = 60000000 pounds
60000000 * 5000 = 300000000000 BTUs burnt
20000Mwh = 20000000kwh
20000000 * 3400 = 68000000000 BTUs output
efficiency = power output / power input
efficiency = 68000000000 / 300000000000 = 0.22666... = 22.6666...%
b)
60000000 pounds of coal are burnt
so 1% of 60000000 = 600000 pounds of sulphur
What your question doesn't state is whether that is 2.2 pounds per million BTUs burnt, or per million BTUs output.
68000000000 BTUs = 68000 million BTUs
300000000000 BTUs = 300000 million BTUs
600000 / 68000 = 8.82... pounds of sulphur per million BTUs output for this plant
600000 / 300000 = 2 pounds of sulphur per million BTUs burnt for this plant
Presumably they mean 2.2 pounds by burnt output, so yes, they do meet the standard.
Subscribe to:
Post Comments (Atom)
No comments:
Post a Comment